Which among the following halides will genera | vedclass

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(D) The stability of a carbocation is determined by resonance,hyperconjugation,and the inductive effect. In the given options,the carbocations formed

Vedclass · Accepted Answer

$(C_6H_5)_3C-Br$

Vedclass · Answer

(D) The stability of a carbocation is determined by resonance,hyperconjugation,and the inductive effect. In the given options,the carbocations formed are: $A$: Allyl carbocation $(CH_2=CH-CH_2^+)$ $B$: Benzyl carbocation $(C_6H_5-CH_2^+)$ $C$: Cyclohexenyl carbocation $D$: Triphenylmethyl carbocation $((C_6H_5)_3C^+)$ Among these,the triphenylmethyl carbocation is the most stable because the positive charge is delocalized over three phenyl rings through extensive resonance. Therefore,$(C_6H_5)_3C-Br$ generates the most stable carbocation.

Column $I$	Column $II$
$A$. $CH_3-CHBr-CD_3$ on treatment with alc. $KOH$ gives $CH_2=CH-CD_3$ as a major product.	$P$. $E1$ reaction
$B$. $Ph-CHBr-CH_3$ reacts faster than $Ph-CHBr-CD_3$.	$Q$. $E2$ reaction
$C$. $Ph-CH_2-CH_2Br$ on treatment with $C_2H_5OD / C_2H_5O^-$ gives $Ph-CD=CH_2$ as the major product.	$R$. $E1cb$ reaction
$D$. $PhCH_2CH_2Br$ and $PhCD_2CH_2Br$ react with same rate.	$S$. First order reaction

Which among the following halides will generate the most stable carbocation in a nucleophilic substitution reaction?

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