Which among the following molecules have sp^3 | vedclass

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(C) To determine the hybridisation and lone pairs,we use the formula: $	ext{Steric Number} = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of

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$(i)$ and $(iii)$ only

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(C) To determine the hybridisation and lone pairs,we use the formula: $	ext{Steric Number} = \frac{1}{2} (V + M - C + A)$,where $V$ is the number of valence electrons,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.$(i)\ SF_4$: $	ext{Steric Number} = \frac{1}{2} (6 + 4) = 5$ $(sp^3d)$. Lone pairs $= 5 - 4 = 1$.$(ii)\ [PCl_4]^+$: $	ext{Steric Number} = \frac{1}{2} (5 + 4 - 1) = 4$ $(sp^3)$. Lone pairs $= 4 - 4 = 0$.$(iii)\ XeO_2F_2$: $	ext{Steric Number} = \frac{1}{2} (8 + 2) = 5$ $(sp^3d)$. Lone pairs $= 5 - 4 = 1$.$(iv)\ ClOF_3$: $	ext{Steric Number} = \frac{1}{2} (7 + 3) = 5$ $(sp^3d)$. Lone pairs $= 5 - 4 = 1$. However,the central atom $Cl$ has $5$ bond pairs (one double bond with $O$ and three single bonds with $F$). Thus,it has $0$ lone pairs.Therefore,molecules $(i)$ and $(iii)$ satisfy the condition.

Which among the following molecules have $sp^3d$ hybridisation with one lone pair of electrons on the central atom?
$(i)\ SF_4$
$(ii)\ [PCl_4]^+$
$(iii)\ XeO_2F_2$
$(iv)\ ClOF_3$

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Which among the following molecules have $sp^3d$ hybridisation with one lone pair of electrons on the central atom?$(i)\ SF_4$$(ii)\ [PCl_4]^+$$(iii)\ XeO_2F_2$$(iv)\ ClOF_3$