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Activation energy for the hydrolysis of sucrose by acid is $X \ kJ \ mol^{-1}$ whereas activation energy for the hydrolysis of sucrose by sucrase is $Y \ kJ \ mol^{-1}$. $X$ and $Y$ respectively are

The equation $k = (6.5 \times 10^{12} \, s^{-1}) e^{-26000 \, K / T}$ is followed for the decomposition of compound $A$. The activation energy for the reaction is $..... \, kJ \, mol^{-1}$. [nearest integer] (Given: $R = 8.314 \, J \, K^{-1} \, mol^{-1}$)

How are the values of $E_a$ and $A$ obtained from the Arrhenius equation?

Which of the following graphs of $\log \, K \rightarrow 1/T$ can be used to calculate the activation energy?

The decomposition of a hydrocarbon follows the equation $K = (4.5 \times 10^{11} \, s^{-1}) e^{-28000 \, K/T}$. What will be the value of activation energy in $KJ \, mol^{-1}$?

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