Which of the following has the maximum boilin | vedclass

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(A) The boiling point of alkanes depends on the surface area of the molecule. As the branching in an alkane increases,its surface area decreases,which

Vedclass · Accepted Answer

$CH_3-CH_2-CH_2-CH_2-CH_3$ (n-pentane)

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(A) The boiling point of alkanes depends on the surface area of the molecule. As the branching in an alkane increases,its surface area decreases,which leads to weaker van der Waals forces of attraction. Therefore,the boiling point decreases as branching increases. Comparing the isomers of pentane $(C_5H_{12})$: $1$. $n$-pentane (straight chain) has the maximum surface area and thus the highest boiling point. $2$. Isopentane ($2$-methylbutane) has one branch. $3$. Neopentane ($2$,$2$-dimethylpropane) has two branches (most branched). Among the given options,$n$-pentane is a straight-chain isomer with no branching,giving it the largest surface area and the highest boiling point.

Which of the following has the maximum boiling point $(B.P.)$?

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