Which has more number of atoms?(i) 100 , g of | vedclass

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(B) $(i)$ For $100 \, g$ of $N_2$:Number of moles $= \frac{100 \, g}{28 \, g/mol} \approx 3.57 \, mol$.Number of molecules $= 3.57 	imes 6.022 	imes

Vedclass · Accepted Answer

$43.01 	imes 10^{23}, 141.69 	imes 10^{23}$

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(B) $(i)$ For $100 \, g$ of $N_2$:Number of moles $= \frac{100 \, g}{28 \, g/mol} \approx 3.57 \, mol$.Number of molecules $= 3.57 	imes 6.022 	imes 10^{23} \approx 21.505 	imes 10^{23}$.Since each $N_2$ molecule has $2$ atoms,total atoms $= 2 	imes 21.505 	imes 10^{23} = 43.01 	imes 10^{23}$.$(ii)$ For $100 \, g$ of $NH_3$:Number of moles $= \frac{100 \, g}{17 \, g/mol} \approx 5.88 \, mol$.Number of molecules $= 5.88 	imes 6.022 	imes 10^{23} \approx 35.42 	imes 10^{23}$.Since each $NH_3$ molecule has $4$ atoms ($1$ Nitrogen $+ 3$ Hydrogen),total atoms $= 4 	imes 35.42 	imes 10^{23} = 141.69 	imes 10^{23}$.Comparing the two,$100 \, g$ of $NH_3$ has more atoms.

Which has more number of atoms?
$(i)$ $100 \, g$ of $N_2$
$(ii)$ $100 \, g$ of $NH_3$

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Which has more number of atoms?$(i)$ $100 \, g$ of $N_2$$(ii)$ $100 \, g$ of $NH_3$