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(C) For a complex to show both geometrical and optical isomerism,it must have at least one geometrical isomer that is chiral (lacks a plane of symmetr

Vedclass · Accepted Answer

$[Cr(en)_2Cl_2]^+$

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(C) For a complex to show both geometrical and optical isomerism,it must have at least one geometrical isomer that is chiral (lacks a plane of symmetry).$1$. $[Pt(NH_3)_2Cl_2]$ is a square planar complex,which shows geometrical isomerism (cis and trans) but not optical isomerism.$2$. $[Cu(NH_3)_4]^{2+}$ is a square planar complex and does not show optical isomerism.$3$. $[Cr(en)_2Cl_2]^+$ is an octahedral complex of the type $[M(AA)_2a_2]$. The $cis$-isomer of this complex is optically active because it lacks a plane of symmetry,while the $trans$-isomer is optically inactive.$4$. $[Co(NH_3)_4Cl_2]^+$ is an octahedral complex of the type $[MA_4a_2]$,which shows geometrical isomerism but its isomers possess planes of symmetry,making them optically inactive.Therefore,$[Cr(en)_2Cl_2]^+$ is the correct answer.

Which of the following complexes will show both geometrical and optical isomerism?

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