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(B) The complex with the maximum number of unpaired electrons will exhibit the maximum attraction to an applied magnetic field (paramagnetism).$1$. $[

Vedclass · Accepted Answer

$[Co(H_2O)_6]^{2+}$

Vedclass · Answer

(B) The complex with the maximum number of unpaired electrons will exhibit the maximum attraction to an applied magnetic field (paramagnetism).$1$. $[Zn(H_2O)_6]^{2+}$: $Zn^{2+}$ is a $d^{10}$ system,which has $0$ unpaired electrons.$2$. $[Co(H_2O)_6]^{2+}$: $Co^{2+}$ is a $d^7$ system. In an octahedral field with a weak field ligand $(H_2O)$,the configuration is $t_{2g}^5 e_g^2$,resulting in $3$ unpaired electrons.$3$. $[Co(en)_3]^{3+}$: $Co^{3+}$ is a $d^6$ system. Since $en$ is a strong field ligand,the configuration is $t_{2g}^6 e_g^0$,resulting in $0$ unpaired electrons.$4$. $[Ni(H_2O)_6]^{2+}$: $Ni^{2+}$ is a $d^8$ system,which has $2$ unpaired electrons.Since $[Co(H_2O)_6]^{2+}$ has the highest number of unpaired electrons $(3)$,it will exhibit the maximum attraction.

Which of the following complexes will exhibit maximum attraction to an applied magnetic field?

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