Which of the following compounds is most reac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Decarboxylation with sodalime $(NaOH + CaO)$ proceeds via the formation of a carbanion intermediate in the rate-determining step. The stability of

Vedclass · Accepted Answer

$O_2N-CH_2-COOH$

Vedclass · Answer

(B) Decarboxylation with sodalime $(NaOH + CaO)$ proceeds via the formation of a carbanion intermediate in the rate-determining step. The stability of the carbanion determines the rate of decarboxylation. Electron-withdrawing groups (EWGs) stabilize the carbanion by dispersing the negative charge,thereby increasing the rate of decarboxylation. Among the given options,the nitro group $(-NO_2)$ in $O_2N-CH_2-COOH$ is a strong electron-withdrawing group,which significantly stabilizes the resulting carbanion $(O_2N-CH_2^-)$. Therefore,$O_2N-CH_2-COOH$ is the most reactive toward decarboxylation.

Which of the following compounds is most reactive toward decarboxylation when reacting with sodalime?

Similar Questions

Given below are two statements :
Statement $I :$ The esterification of carboxylic acid with an alcohol is a nucleophilic acyl substitution.
Statement $II :$ Electron withdrawing groups in the carboxylic acid will increase the rate of esterification reaction.
Choose the most appropriate option

Order of acidity of benzoic acid $(I)$,$4-$methoxybenzoic acid $(II)$,acetic acid $(III)$ and $4-$nitrobenzoic acid $(IV)$ is

Identify the final products in the following sequence of reactions: $RCOOH + R'OH \xrightarrow{H^+} \text{intermediate} \xrightarrow[\Delta]{Ni, H_2} \text{Products}$

Treatment of benzoic acid with $Cl_2/FeCl_3$ will give

Write the structure of the product of the following reaction.

Vedclass Test Series

Exam Paper Generator

Online Exam Module