Which of the following compounds will not sho | vedclass

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(D) Tautomerism requires the presence of at least one $\alpha$-hydrogen atom adjacent to a carbonyl group $(-C=O)$ or similar functional group.$1$. $1

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All of these

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(D) Tautomerism requires the presence of at least one $\alpha$-hydrogen atom adjacent to a carbonyl group $(-C=O)$ or similar functional group.$1$. $1,4$-Benzoquinone: It has no $\alpha$-hydrogen atoms adjacent to the carbonyl groups,as the carbons are part of a double bond in the ring.$2$. Cyclobut$-2-$enone: The $\alpha$-carbon (at position $4$) has two hydrogen atoms,so it can show tautomerism.$3$. $2,2,6,6$-Tetramethylcyclohexanone: The $\alpha$-carbons (positions $2$ and $6$) are fully substituted with methyl groups and have no $\alpha$-hydrogen atoms,so it cannot show tautomerism.Since both $1,4$-Benzoquinone and $2,2,6,6$-Tetramethylcyclohexanone do not show tautomerism,the question implies identifying which of the given options do not show it. However,based on standard chemistry problems of this type,if multiple options are correct,the question might be flawed or intended to be 'Which of the following...'. Given the options,$1,4$-Benzoquinone and $2,2,6,6$-Tetramethylcyclohexanone both lack $\alpha$-hydrogens. If we must choose one,$2,2,6,6$-Tetramethylcyclohexanone is a classic example of a ketone lacking $\alpha$-hydrogens.

Which of the following compounds will not show tautomerism?

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