The following reaction gives:

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The reaction is a Cross Cannizzaro reaction between $3,4-$dimethoxybenzaldehyde and formaldehyde $(HCHO)$ in the presence of concentrated $NaOH$.I

Vedclass · Accepted Answer

$3,4-$Dimethoxybenzyl alcohol + Formate ion

Vedclass · Answer

(B) The reaction is a Cross Cannizzaro reaction between $3,4-$dimethoxybenzaldehyde and formaldehyde $(HCHO)$ in the presence of concentrated $NaOH$.In a Cross Cannizzaro reaction,the more reactive aldehyde (formaldehyde) is oxidized to the corresponding acid salt (formate,$HCOO^-$),and the less reactive aldehyde ($3$,$4$-dimethoxybenzaldehyde) is reduced to the corresponding alcohol ($3$,$4$-dimethoxybenzyl alcohol).Therefore,the products are $3,4-$dimethoxybenzyl alcohol and the formate ion $(HCOO^-)$.

Similar Questions

The relation between $K_1$ and $K_2$ for the given equilibrium reactions is:

Compound '$X$' (molecular formula $C_3H_8O$) reacts with acidic potassium dichromate to give product '$Y$' (molecular formula $C_3H_6O$). '$Y$' gives a silver mirror test. When '$Y$' is reacted with aqueous $NH_2CONHNH_2$ and sodium acetate,it gives product '$Z$'. What is the structure of '$Z$'?

$CH_3CHO$ $\xrightarrow[5\,^{\circ}C]{10\%\,NaOH}$ $\xrightarrow[\Delta]{}$ $\xrightarrow[Ni]{H_2} (A)$; Product $(A)$ of the reaction is

The compound that does not undergo haloform reaction is

Give applications of cyanohydrins with acetaldehyde with suitable reactions. $OR$ Give following conversions by using acetaldehyde as starting material.
$(a)$ Lactic acid and acrylic acid
$(b)$ Alanine
$(c)$ $1$-amino propane-$2$-ol

Vedclass Test Series

Exam Paper Generator

Online Exam Module