Which of the following compounds has the high | vedclass

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(B) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each metal ion:$1$. In $Ni(NO_3)_2$,$Ni$ is in the $+2$ ox

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$MnSO_4$

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(B) To determine the magnetic moment,we calculate the number of unpaired electrons $(n)$ in each metal ion:$1$. In $Ni(NO_3)_2$,$Ni$ is in the $+2$ oxidation state $(3d^8)$. It has $n = 2$ unpaired electrons.$2$. In $MnSO_4$,$Mn$ is in the $+2$ oxidation state $(3d^5)$. It has $n = 5$ unpaired electrons.$3$. In $CrCl_3$,$Cr$ is in the $+3$ oxidation state $(3d^3)$. It has $n = 3$ unpaired electrons.$4$. In $FeSO_4$,$Fe$ is in the $+2$ oxidation state $(3d^6)$. It has $n = 4$ unpaired electrons.The magnetic moment is given by the formula $\mu = \sqrt{n(n+2)} \ BM$. Since $Mn^{2+}$ has the highest number of unpaired electrons $(n=5)$,it will have the highest magnetic moment.

Which of the following compounds has the highest magnetic moment?

Similar Questions

Which of the following statements is not correct?

What is the magnetic moment value of $Ni^{2+}$ in an aqueous solution in Bohr Magnetons? (Atomic number: $Ni = 28$)

What is the magnetic moment value of $Cr(CO)_6$ in Bohr Magneton units?

Among the following complexes,the total number of diamagnetic species is. . . . $[Mn(NH_3)_6]^{3+}, [MnCl_6]^{3-}, [FeF_6]^{3-}, [CoF_6]^{3-}, [Fe(NH_3)_6]^{3+}$ and $[Co(en)_3]^{3+}$
[Given,atomic number: $Mn=25, Fe=26, Co=27$; $en=H_2NCH_2CH_2NH_2$ ]

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