Which of the following compounds is most stab | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The stability of substituted cyclohexanes depends on the orientation of the substituents. Substituents in the equatorial $(e)$ position are more s

Vedclass · Accepted Answer

Vedclass · Answer

(D) The stability of substituted cyclohexanes depends on the orientation of the substituents. Substituents in the equatorial $(e)$ position are more stable than those in the axial $(a)$ position due to reduced $1,3$-diaxial interactions (steric repulsion).For $1,4$-dimethylcyclohexane,the $trans$ isomer can adopt a conformation where both methyl groups are in the equatorial position $(e, e)$.This $trans$-$1,4$-dimethylcyclohexane $(e, e)$ conformation is the most stable as it minimizes steric repulsion compared to the $cis$ isomer (which must be $a, e$) or other axial-containing conformations.

Which of the following compounds is most stable?

Similar Questions

What is stereoisomerism? Which are its types?

Isomers have the same ...........

Determine the configuration of the chiral centers in the given structure.

The possible number of stereoisomers of the product of the following reaction would be: $Ph - CH = CH - CH(CH_3) - CHO \xrightarrow[pH = 4.5]{H_2N - OH}$ ?

Which of the following compounds does not exhibit keto-enol tautomerism?

Vedclass Test Series

Exam Paper Generator

Online Exam Module