Which of the following does not show optical | vedclass

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(A) Optical isomerism is exhibited by only those complexes in which elements of symmetry are absent.Octahedral complexes of the types $[M(aa)_3]$,$[M(

Vedclass · Accepted Answer

$[Co(NH_3)_3Cl_3]^0$

Vedclass · Answer

(A) Optical isomerism is exhibited by only those complexes in which elements of symmetry are absent.Octahedral complexes of the types $[M(aa)_3]$,$[M(aa)x_2y_2]$,and $[M(aa)_2x_2]$ lack elements of symmetry and thus exhibit optical isomerism,where $aa$ represents a bidentate ligand,$x$ or $y$ represent monodentate ligands,and $M$ represents the central metal ion.Complexes of the type $[MA_3B_3]$,such as $[Co(NH_3)_3Cl_3]^0$,possess planes of symmetry and therefore do not exhibit optical isomerism.Conversely,$[Co(en)_3]^{3+}$ (type $[M(aa)_3]$),$[Co(en)_2Cl_2]^+$ (type $[M(aa)_2x_2]$),and $[Co(en)Cl_2(NH_3)_2]^+$ (type $[M(aa)x_2y_2]$) all exhibit optical isomerism.

Which of the following does not show optical isomerism?
$(en = \text{ethylenediamine})$

Similar Questions

Which of the following would exhibit coordination isomerism?

$[Cr(NH_3)_6]^{3+}$ is paramagnetic while $[Ni(CN)_4]^{2-}$ is diamagnetic. Explain why?

Which of the following complexes will show coordination isomerism?
$A. [Ag(NH_3)_2][Ag(CN)_2]$
$B. [Co(NH_3)_6][Cr(CN)_6]$
$C. [Co(NH_3)_6][Co(CN)_6]$
$D. [Fe(NH_3)_6][Co(CN)_6]$
$E. [Co(NH_3)_6][Fe(CN)_6]$
Choose the correct answer from the options given below:

Assertion : $[Fe(CN)_6]^{3-}$ is weakly paramagnetic while $[Fe(CN)_6]^{4-}$ is diamagnetic.
Reason : $[Fe(CN)_6]^{3-}$ has $+3$ oxidation state while $[Fe(CN)_6]^{4-}$ has $+2$ oxidation state.

Explain different types of structural isomerism in coordination compounds.

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Which of the following does not show optical isomerism?$(en = \text{ethylenediamine})$