Which of the following electronic configurati | vedclass

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(D) The $I.P.$ (Ionization Potential) depends on the stability of the electronic configuration and the shielding effect.Comparing the given configurat

Vedclass · Accepted Answer

$1s^2 2s^2 2p^6 3s^2 3p^1$

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(D) The $I.P.$ (Ionization Potential) depends on the stability of the electronic configuration and the shielding effect.Comparing the given configurations:$A$: $3p^6$ (Noble gas,very stable,high $I.P.$)$B$: $3p^5$ (High $I.P.$ due to high effective nuclear charge)$C$: $3s^2$ (Fully filled $s$-orbital,stable,high $I.P.$)$D$: $3s^2 3p^1$ (The electron is being removed from the $3p$ orbital,which is shielded by the $3s^2$ electrons and is further from the nucleus compared to the $3s$ orbital).Therefore,the configuration $1s^2 2s^2 2p^6 3s^2 3p^1$ has the least $I.P.$ value.

Which of the following electronic configurations will have the least $I.P.$ value?

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