Which of the following equations has 2 as a r | vedclass

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Question

(A) To determine if $x = 2$ is a root of an equation,we substitute $x = 2$ into each equation and check if the result is $0$.$(A)$ For $2x^2 - 7x + 6

Vedclass · Accepted Answer

$2x^2 - 7x + 6 = 0$

Vedclass · Answer

(A) To determine if $x = 2$ is a root of an equation,we substitute $x = 2$ into each equation and check if the result is $0$.$(A)$ For $2x^2 - 7x + 6 = 0$:$2(2)^2 - 7(2) + 6 = 2(4) - 14 + 6 = 8 - 14 + 6 = 0$.Since the result is $0$,$x = 2$ is a root of this equation.$(B)$ For $x^2 + 3x - 12 = 0$:$(2)^2 + 3(2) - 12 = 4 + 6 - 12 = -2 
eq 0$.So,$x = 2$ is not a root.$(C)$ For $x^2 - 4x + 5 = 0$:$(2)^2 - 4(2) + 5 = 4 - 8 + 5 = 1 
eq 0$.So,$x = 2$ is not a root.$(D)$ For $3x^2 - 6x - 2 = 0$:$3(2)^2 - 6(2) - 2 = 12 - 12 - 2 = -2 
eq 0$.So,$x = 2$ is not a root.Therefore,the correct equation is $2x^2 - 7x + 6 = 0$.

Which of the following equations has $2$ as a root?

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