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(A) diode is forward-biased when the potential at the $p$-side (anode) is higher than the potential at the $n$-side (cathode).In the given circuits,th

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$A$

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(A) diode is forward-biased when the potential at the $p$-side (anode) is higher than the potential at the $n$-side (cathode).In the given circuits,the triangle represents the $p$-side and the vertical bar represents the $n$-side.For option $A$: $V_p = 0 \ V$,$V_n = -4 \ V$. Since $0 \ V > -4 \ V$,the diode is forward-biased.For option $B$: $V_p = -4 \ V$,$V_n = -3 \ V$. Since $-4 \ V For option $C$: $V_p = -2 \ V$,$V_n = +2 \ V$. Since $-2 \ V For option $D$: $V_p = 3 \ V$,$V_n = 5 \ V$. Since $3 \ V Therefore,the correct figure is $A$.

Which of the following figures represents a forward-biased diode?

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