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(B) Resonance energy is directly related to the stability of a molecule and the extent of delocalization of $\pi$-electrons. $A$: $3,4-	ext{dihydro}-

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(B) Resonance energy is directly related to the stability of a molecule and the extent of delocalization of $\pi$-electrons. $A$: $3,4-	ext{dihydro}-2H-	ext{pyran}$ is a non-aromatic molecule with only one double bond. $B$: The pyrylium cation is a six-membered heterocyclic aromatic ring. It follows $H$ückel's rule ($4n+2$ $\pi$-electrons,where $n=1$,total $6$ $\pi$-electrons). Aromatic compounds possess significantly higher resonance energy compared to non-aromatic or anti-aromatic systems. $C$ and $D$: $4H-	ext{pyran}$ and $2H-	ext{pyran}$ are non-aromatic because they contain an $sp^3$ hybridized carbon atom in the ring,which breaks the continuous conjugation. Therefore,the pyrylium cation has the highest resonance energy due to its aromatic character.

Which of the following has the highest resonance energy?

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