Which of the following molecules has the smal | vedclass

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(A) To determine the bond angle,we look at the hybridization and the number of lone pairs on the central atom:$1$. $CO_2$: $sp$ hybridization,linear g

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$H_2O$

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(A) To determine the bond angle,we look at the hybridization and the number of lone pairs on the central atom:$1$. $CO_2$: $sp$ hybridization,linear geometry,bond angle = $180^{\circ}$.$2$. $CH_4$: $sp^3$ hybridization,tetrahedral geometry,bond angle = $109.5^{\circ}$.$3$. $NH_3$: $sp^3$ hybridization,trigonal pyramidal geometry,one lone pair,bond angle = $107^{\circ}$.$4$. $H_2O$: $sp^3$ hybridization,bent geometry,two lone pairs,bond angle = $104.5^{\circ}$.Due to the presence of two lone pairs on the oxygen atom in $H_2O$,the lone pair-lone pair repulsion is greater than the lone pair-bond pair repulsion,which compresses the $H-O-H$ bond angle to $104.5^{\circ}$,the smallest among the given options.

$List-I$ (Compound)	$List-II$ (Shape)
$A$. $BrF_5$	$I$. bent
$B$. $[CrF_6]^{3-}$	$II$. square pyramidal
$C$. $O_3$	$III$. trigonal bipyramidal
$D$. $PCl_5$	$IV$. octahedral

Which of the following molecules has the smallest bond angle?

Similar Questions

Of the following species,the one having a square planar structure is:

Which of the following is the incorrect order of bond angle?

The shape of $XeO_2F_2$ molecule is

Match $List-I$ with $List-II$.
$List-I$ (Compound) $List-II$ (Shape)
$A$. $BrF_5$ $I$. bent
$B$. $[CrF_6]^{3-}$ $II$. square pyramidal
$C$. $O_3$ $III$. trigonal bipyramidal
$D$. $PCl_5$ $IV$. octahedral

Choose the correct answer from the options given below.

Which of the following is the correct order of bond angle?

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