Which of the following ions is paramagnetic?

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(C) To determine if an ion is paramagnetic,we check for the presence of unpaired electrons in its electronic configuration:$1. Cu^{+} (Z=29): [Ar] 3d^

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$Ti^{3+}$

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(C) To determine if an ion is paramagnetic,we check for the presence of unpaired electrons in its electronic configuration:$1. Cu^{+} (Z=29): [Ar] 3d^{10} 4s^{0}$. All electrons are paired,so it is diamagnetic.$2. Zn^{2+} (Z=30): [Ar] 3d^{10} 4s^{0}$. All electrons are paired,so it is diamagnetic.$3. Ti^{3+} (Z=22): [Ar] 3d^{1} 4s^{0}$. It has one unpaired electron in the $3d$ orbital,making it paramagnetic.$4. Ti^{4+} (Z=22): [Ar] 3d^{0} 4s^{0}$. It has no electrons in the $d$ orbital,so it is diamagnetic.Therefore,the correct option is $(C)$.

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