Which of the following is more basic than ani | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Benzylamine,$C_{6}H_{5}CH_{2}NH_{2}$,is more basic than aniline because the benzyl group $(C_{6}H_{5}CH_{2}-)$ is an electron-donating group due t

Vedclass · Accepted Answer

Benzylamine

Vedclass · Answer

(A) Benzylamine,$C_{6}H_{5}CH_{2}NH_{2}$,is more basic than aniline because the benzyl group $(C_{6}H_{5}CH_{2}-)$ is an electron-donating group due to the $+I$ effect. This increases the electron density on the nitrogen atom of the $-NH_{2}$ group,making the lone pair more available for donation. In contrast,phenyl and nitro groups are electron-withdrawing groups ($-I$ or $-M$ effects),which decrease the electron density on the nitrogen atom. Therefore,diphenylamine,triphenylamine,and $p-$nitroaniline are less basic than aniline.

Which of the following is more basic than aniline?

Similar Questions

Which one of the following compounds forms a quaternary salt on reacting with excess methyl iodide?

In the reaction $C_6H_5NH_2 + CHCl_3 + 3KOH \rightarrow A + 3KCl + 3H_2O$,what is '$A$'?

$C_6H_5CH_2Cl$ $\xrightarrow{\text{Alc. } NH_3} A$ $\xrightarrow{2 CH_3Cl} B$. The product $B$ is

Identify the product $Z$ in the following reaction:
$C_6H_5NH_2$ $\xrightarrow{(Ac)_2O} X$ $\xrightarrow{Br_2/CCl_4} Y$ $\xrightarrow{HOH} Z$

The correct order of basic strength of Pyrrole,Pyridine,and Piperidine is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module