Which of the following is more stable than th | vedclass

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(C) The stability of carbanions is primarily determined by the inductive effect. Alkyl groups are electron-donating ($+I$ effect). Since carbanions al

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Methyl anion

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(C) The stability of carbanions is primarily determined by the inductive effect. Alkyl groups are electron-donating ($+I$ effect). Since carbanions already possess a negative charge,the presence of electron-donating groups increases the electron density on the carbon atom,which destabilizes the carbanion. Therefore,the stability order is: $	ext{Methyl anion} > 	ext{Ethyl anion} > 	ext{Isobutyl anion} > t-	ext{Butyl anion}$. Among the given options,the methyl anion $(CH_3^-)$ is the most stable because it has no electron-donating alkyl groups attached to the negatively charged carbon.

Which of the following is more stable than the remaining three?

Similar Questions

Arrange the following carbanions in the decreasing order of their stability:
$(1) CH_3-CH_2^-, (2) CH_2=CH^-, (3) HC \equiv C^-$

Which of the following options given below is incorrect?

Consider the following compound $(X)$:
$H-C \equiv C-CH_2-CH(CH_3)-CH_3$
The most stable and least stable carbon radicals,respectively,produced by homolytic cleavage of the corresponding $C-H$ bond are:

Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

Which of the following carbocations is expected to be most stable?

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