(B) To find the roots of $f(x) = x^3 - 11x^2 + 36x - 36 = 0$,we factor the polynomial:$x^3 - 2x^2 - 9x^2 + 18x + 18x - 36 = 0$$x^2(x - 2) - 9x(x - 2)

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(B) To find the roots of $f(x) = x^3 - 11x^2 + 36x - 36 = 0$,we factor the polynomial:$x^3 - 2x^2 - 9x^2 + 18x + 18x - 36 = 0$$x^2(x - 2) - 9x(x - 2) + 18(x - 2) = 0$$(x - 2)(x^2 - 9x + 18) = 0$$(x - 2)(x - 3)(x - 6) = 0$The roots are $x = 2, 3, 6$.Therefore,$x = 4$ is not a root of the given polynomial.

Class 11 Mathematics 4-2.Quadratic Equations and Inequations Solution of quadratic equations and Nature of roots

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Which of the following is not a root of $f(x) = x^3 - 11x^2 + 36x - 36$?

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A
$2$
B
$4$
C
$3$
D
$6$

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Which of the following is not a root of $f(x) = x^3 - 11x^2 + 36x - 36$?

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