Which of the following is the correct order f | vedclass

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(C) The correct order of bond angle is $H_3Te^{+} < H_3Se^{+} < H_3S^{+} < H_3O^{+}$.Explanation:$(a)$ In $NH_3$ group hydrides,as the electronegativi

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$H_3Te^{+} < H_3Se^{+} < H_3S^{+} < H_3O^{+}$

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(C) The correct order of bond angle is $H_3Te^{+} Explanation:$(a)$ In $NH_3$ group hydrides,as the electronegativity of the central atom decreases,the bond angle decreases: $NH_3 > PH_3 > AsH_3 > SbH_3$.$(b)$ In $OF_2$ and $H_2O$,the bond angle is affected by the electronegativity of the surrounding atoms. The correct order is $OF_2 $(c)$ In $H_3X^{+}$ species,as the electronegativity of the central atom $X$ increases,the bond angle increases. Thus,$H_3Te^{+} $(d)$ In $BX_3$ molecules,the bond angle is $120^{\circ}$ for all due to $sp^2$ hybridization,so $BF_3 = BCl_3 = BBr_3 = BI_3$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A. SF_4$	$I. T\text{-shaped}$
$B. ClF_3$	$II. \text{Square planar}$
$C. BrF_5$	$III. \text{See-saw}$
$D. XeF_4$	$IV. \text{Square pyramidal}$

Which of the following is the correct order for increasing bond angle?

Similar Questions

Which of the following is an incorrect match regarding the geometry of the molecules?

Match the molecules in List-$I$ with their respective shapes in List-$II$.
List-$I$ (Molecule) List-$II$ (Shape)
$A. SF_4$ $I. T\text{-shaped}$
$B. ClF_3$ $II. \text{Square planar}$
$C. BrF_5$ $III. \text{See-saw}$
$D. XeF_4$ $IV. \text{Square pyramidal}$

What is the $\angle HOH$ bond angle in the $H_2O$ molecule?

Although geometries of $NH_3$ and $H_2O$ molecules are distorted tetrahedral,bond angle in water is less than that of ammonia. Discuss.

Which of the following is not tetrahedral?

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