Which of the following is the correct decreas | vedclass

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(B) To determine the bond angle,we look at the hybridization and the number of lone pairs:$1$. $C_2H_2$ ($sp$ hybridization,linear): $180^{\circ}$$2$.

Vedclass · Accepted Answer

$C_2H_2 > CH_4 > NH_3 > H_2O$

Vedclass · Answer

(B) To determine the bond angle,we look at the hybridization and the number of lone pairs:$1$. $C_2H_2$ ($sp$ hybridization,linear): $180^{\circ}$$2$. $CH_4$ ($sp^3$ hybridization,tetrahedral): $109.5^{\circ}$$3$. $NH_3$ ($sp^3$ hybridization,trigonal pyramidal,$1$ lone pair): $107^{\circ}$$4$. $H_2O$ ($sp^3$ hybridization,bent,$2$ lone pairs): $104.5^{\circ}$Thus,the correct decreasing order is $C_2H_2 > CH_4 > NH_3 > H_2O$.

Which of the following is the correct decreasing order of bond angles?

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