Which of the following is the strongest base?

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(D) To determine the strongest base,we evaluate the availability of the lone pair on the nitrogen atom for protonation.$1$. In $C_6H_5NH_2$ (aniline),

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$C_6H_5CH_2NH_2$

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(D) To determine the strongest base,we evaluate the availability of the lone pair on the nitrogen atom for protonation.$1$. In $C_6H_5NH_2$ (aniline),the lone pair on $N$ is in conjugation with the benzene ring,making it less available.$2$. In $C_6H_5NHCH_3$ ($N$-methylaniline),the $+I$ effect of the $-CH_3$ group increases electron density on $N$,but it is still less basic than aliphatic amines due to resonance.$3$. In $o-CH_3C_6H_4NH_2$ ($o$-toluidine),the ortho-effect reduces basicity compared to aniline.$4$. In $C_6H_5CH_2NH_2$ (benzylamine),the $-NH_2$ group is attached to an $sp^3$ hybridized carbon,not directly to the benzene ring. Therefore,there is no resonance stabilization of the lone pair with the ring. It behaves like an aliphatic primary amine,which is significantly more basic than aromatic amines.

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