Which of the following metal ions will form c | vedclass

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(C) $Cu^{2+}$ ($3d^9$ configuration) forms complexes with the same magnetic moment and geometry irrespective of the nature of the ligand.The electroni

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$Cu^{2+}$

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(C) $Cu^{2+}$ ($3d^9$ configuration) forms complexes with the same magnetic moment and geometry irrespective of the nature of the ligand.The electronic configuration of $Cu^{2+}$ is $[Ar] 3d^9$. The $3d$ subshell contains one unpaired electron.Since the $3d$ subshell is almost completely filled,the incoming ligands cannot cause any pairing or redistribution of electrons in the $3d$ orbitals. Therefore,the number of unpaired electrons remains $1$ (magnetic moment $\mu = \sqrt{1(1+2)} = \sqrt{3} \approx 1.73 \ BM$) regardless of whether the ligand is strong or weak.Furthermore,the geometry of $Cu^{2+}$ complexes is typically determined by the number of ligands (e.g.,square planar for $4$ ligands due to Jahn-Teller distortion),which remains consistent for a given coordination number.

Which of the following metal ions will form complexes with the same magnetic moment and geometry irrespective of the nature of ligands?

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