In which of the following ions is the spin-on | vedclass

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(A) The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. The lower

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$[Ti(H_2O)_6]^{3+}$

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(A) The spin-only magnetic moment is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons. The lower the number of unpaired electrons,the lower the magnetic moment.IonElectronic ConfigurationNumber of Unpaired Electrons $(n)$$[Ti(H_2O)_6]^{3+}$$3d^1$$1$$[Mn(H_2O)_6]^{2+}$$3d^5$$5$$[Ni(H_2O)_6]^{2+}$$3d^8$$2$$[Co(H_2O)_6]^{2+}$$3d^7$$3$Since $[Ti(H_2O)_6]^{3+}$ has the lowest number of unpaired electrons $(n=1)$,it has the lowest spin-only magnetic moment.

In which of the following ions is the spin-only magnetic moment the lowest?

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