Which of the following orders correctly depic | vedclass

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(B) The stability of a carbanion is increased by electron-withdrawing groups $(EWG)$ that disperse the negative charge through inductive $(-I)$ or res

Vedclass · Accepted Answer

$(CHO)_2\overset{\Theta}{C}H > CHO\overset{\Theta}{C}H_2 > \overset{\Theta}{C}H_3$

Vedclass · Answer

(B) The stability of a carbanion is increased by electron-withdrawing groups $(EWG)$ that disperse the negative charge through inductive $(-I)$ or resonance $(-M)$ effects. Conversely,electron-donating groups $(EDG)$ decrease stability by intensifying the negative charge.$1$. In option $B$,the stability order is $(CHO)_2\overset{\Theta}{C}H > CHO\overset{\Theta}{C}H_2 > \overset{\Theta}{C}H_3$. This is correct because the $-CHO$ group exerts a strong $-M$ effect,and having two such groups provides more stabilization than one.$2$. In option $C$,the correct order of stability is $\overset{\Theta}{C}H_2NO_2 > \overset{\Theta}{C}H_2CN > \overset{\Theta}{C}H_2Cl > \overset{\Theta}{C}H_2CH_3$. This is based on the strength of the electron-withdrawing groups: $-NO_2$ (strong $-M$) > $-CN$ $(-I, -M)$ > $-Cl$ $(-I)$ > $-CH_3$ ($+I$,destabilizing).

Which of the following orders correctly depicts the decreasing order of stability of carbanion?

Similar Questions

The correct order of stability for the following alkoxides is:
$(A)$ $CH_3CH(NO_2)O^-$
$(B)$ $CH_2=C(NO_2)O^-$
$(C)$ $O_2N-CH=CH-O^-$

Identify the atoms or groups from the following that exhibit $-R$ effect and $+R$ effect when present on a benzene ring:
$-OR, -NHCOR, -CN, -X, -NO_2, -NH_2, -CHO$

Given below are two statements:
Statement $I$: On the basis of inductive effect, the order of stability of alkyl carbanions is $CH_3^- > CH_3CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-$.
Statement $II$: Allyl and benzyl carbanions are more stabilised by inductive effect and not by resonance effect.

What is the type of delocalization involving $\sigma$ bond orbitals called?

Which of the indicated $H$ in the following is most acidic?

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