Which of the following pairs has a similar ma | vedclass

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(B) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.
For $Fe^{3+

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$Fe^{3+}, Mn^{2+}$

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(B) The magnetic moment $(\mu)$ is calculated using the formula $\mu = \sqrt{n(n+2)} \ BM$,where $n$ is the number of unpaired electrons.
For $Fe^{3+}$ $(Z=26)$: The electronic configuration is $[Ar] 3d^5$. The number of unpaired electrons $(n)$ = $5$.
For $Mn^{2+}$ $(Z=25)$: The electronic configuration is $[Ar] 3d^5$. The number of unpaired electrons $(n)$ = $5$.
Since both $Fe^{3+}$ and $Mn^{2+}$ have $5$ unpaired electrons,they have the same magnetic moment of $\sqrt{5(5+2)} = \sqrt{35} \ BM$.

$E^{\Theta }$	$V$	$Cr$	$Mn$	$Fe$	$Co$	$Ni$	$Cu$
$(M^{2+}/M)$	$-1.18$	$-0.91$	$-1.18$	$-0.44$	$-0.28$	$-0.25$	$+0.35$

List-$I$ (Property)	List-$II$ (Metal)
$A$. Element with maximum second ionization enthalpy	$i$. $Co$
$B$. Element with maximum third ionization enthalpy	$ii$. $Cr$
$C$. $M$ in $M(CO)_6$	$iii$. $Cu$
$D$. Element with maximum enthalpy of atomization	$iv$. $Zn$
	$v$. $Ni$

Which of the following pairs has a similar magnetic moment?

Similar Questions

In the $3d$ series of $d-$block elements,which of the following elements has the maximum atomic size?

For the first row transition metals,the $E^{\Theta }$ values are:

$E^{\Theta }$ $V$ $Cr$ $Mn$ $Fe$ $Co$ $Ni$ $Cu$

$(M^{2+}/M)$ $-1.18$ $-0.91$ $-1.18$ $-0.44$ $-0.28$ $-0.25$ $+0.35$

Explain the irregularity in the above values.

The magnetic moment of a metal ion of the first transition series is $2.83 \ BM$. Therefore,it will have how many unpaired electrons?

Identify the transition element.

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