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(A) In a nuclear reaction,both the total atomic number and the total mass number must be conserved on both sides of the equation.Let the emitted parti

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$_{0}n^{1}$

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(A) In a nuclear reaction,both the total atomic number and the total mass number must be conserved on both sides of the equation.Let the emitted particle be $_{z}X^{a}$.The reaction is: $_{13}Al^{27} + _{2}He^{4} 	o _{15}P^{30} + _{z}X^{a}$.Equating the mass numbers: $27 + 4 = 30 + a \implies 31 = 30 + a \implies a = 1$.Equating the atomic numbers: $13 + 2 = 15 + z \implies 15 = 15 + z \implies z = 0$.The particle is $_{0}n^{1}$,which is a neutron.

Which of the following particles is emitted in the reaction $_{13}Al^{27} + _{2}He^{4} \to _{15}P^{30} + .....$?

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