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(D) Solution $1$ consists of $10 \ mol$ of solute $x$ in $10 \ L$ of water,resulting in a concentration of $1 \ mol/L$.Solution $2$ is prepared by tak

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Gibbs free energy

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(D) Solution $1$ consists of $10 \ mol$ of solute $x$ in $10 \ L$ of water,resulting in a concentration of $1 \ mol/L$.Solution $2$ is prepared by taking $1 \ L$ of solution $1$ (which contains $1 \ mol$ of $x$ and $1 \ L$ of water) and adding $1 \ mol$ of solute $x$ and $1 \ L$ of water.Total amount in solution $2$ is $2 \ mol$ of $x$ in $2 \ L$ of water,so the concentration remains $1 \ mol/L$.Since the concentration and composition are identical,intensive properties like density and molar heat capacity remain unchanged.Gibbs free energy $(G)$ is an extensive property,which depends on the total amount of matter in the system.Since the total amount of substance in solution $1$ is greater than in solution $2$,the Gibbs free energy will change.

Which of the following properties will change when the system containing solution $1$ becomes solution $2$?

$10 \ mol$ of solute $x + 10 \ L$ of water $1 \ L$ of solution $1 + 1 \ mol$ of solute $x + 1 \ L$ of water

(Solution $1$) (Solution $2$)

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Which of the following properties will change when the system containing solution $1$ becomes solution $2$? $10 \ mol$ of solute $x + 10 \ L$ of water $1 \ L$ of solution $1 + 1 \ mol$ of solute $x + 1 \ L$ of water (Solution $1$) (Solution $2$)