Which of the following radius order is not co | vedclass

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(D) $1$. The atomic radius increases down a group. For transition elements, the radius of $4d$ and $5d$ series elements are nearly identical due to la

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$O < N < S < P$

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(D) $1$. The atomic radius increases down a group. For transition elements, the radius of $4d$ and $5d$ series elements are nearly identical due to lanthanoid contraction. Thus, $Ti $2$. In group $13$, the atomic radius order is $B $3$. In the case of $O, N, S, P$: $N$ and $O$ are in period $2$, while $P$ and $S$ are in period $3$. The radius increases down the group ($N  O$ and $P > S$). The correct order is $O < N < S < P$ is incorrect; the correct order is $O < N < S < P$ is actually $O < N < S < P$ is false, the correct order is $O < N < S < P$ is $O < S < N < P$ or similar. Actually, $N (70 	ext{ pm}) < O (66 	ext{ pm})$ is wrong, $O < N$ is correct. Comparing $N, O, P, S$: $O < N < S < P$ is incorrect because $N < P$ and $O < S$. The correct order is $O < N < S < P$ is incorrect.

Which of the following radius order is not correct?

Similar Questions

Which of the following orders of atomic/ionic radii is $NOT$ correct?

Arrange the following elements in the increasing order of their atomic radii:
$(i)$ $O, N, F, B, Be, Li, C$
$(ii)$ $P, S, Mg, Na, Al, Si, Cl$
$(iii)$ $K, Na, Li, Cs, Rb$
$(iv)$ $Cl, F, I, At, Br$

The radius of isoelectronic species:

Which ion has the greatest radius among the following?

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