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(D) The reaction of alcohols with $HCl$ to form alkyl halides is known as the $Groove's$ process.$I$. Primary alcohols like $CH_3CH_2OH$ require the c

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$I$,$III$ and $IV$ only

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(D) The reaction of alcohols with $HCl$ to form alkyl halides is known as the $Groove's$ process.$I$. Primary alcohols like $CH_3CH_2OH$ require the catalyst anhydrous $ZnCl_2$ to proceed.$II$. Primary alcohols do not react with $HCl$ in the absence of $ZnCl_2$.$III$. Tertiary alcohols like $(CH_3)_3COH$ are highly reactive and form alkyl halides with $HCl$ even at room temperature without $ZnCl_2$ due to the formation of a stable tertiary carbocation.$IV$. Secondary alcohols like $(CH_3)_2CHOH$ require anhydrous $ZnCl_2$ to react with $HCl$.Therefore,reactions $I$,$III$,and $IV$ are suitable for the preparation of alkyl halides.

Which of the following reaction$(s)$ can be used for the preparation of alkyl halides?
$I$. $CH_3CH_2OH + HCl \xrightarrow{Anh. ZnCl_2}$
$II$. $CH_3CH_2OH + HCl \rightarrow$
$III$. $(CH_3)_3COH + HCl \rightarrow$
$IV$. $(CH_3)_2CHOH + HCl \xrightarrow{Anh. ZnCl_2}$

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Which of the following reaction$(s)$ can be used for the preparation of alkyl halides?$I$. $CH_3CH_2OH + HCl \xrightarrow{Anh. ZnCl_2}$$II$. $CH_3CH_2OH + HCl \rightarrow$$III$. $(CH_3)_3COH + HCl \rightarrow$$IV$. $(CH_3)_2CHOH + HCl \xrightarrow{Anh. ZnCl_2}$