Which of the following sets of reagents conve | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The conversion of aniline to chlorobenzene is a two-step process known as the Sandmeyer reaction. Step $1$: Aniline $(C_6H_5NH_2)$ reacts with $Na

Vedclass · Accepted Answer

$NaNO_2 / HCl, 273-278 \ K ; Cu_2Cl_2 / HCl$

Vedclass · Answer

(A) The conversion of aniline to chlorobenzene is a two-step process known as the Sandmeyer reaction. Step $1$: Aniline $(C_6H_5NH_2)$ reacts with $NaNO_2 / HCl$ at a low temperature of $273-278 \ K$ $(0-5 \ ^\circ C)$ to form benzene diazonium chloride $(C_6H_5N_2^+Cl^-)$. Step $2$: The benzene diazonium chloride is then treated with cuprous chloride $(Cu_2Cl_2)$ in the presence of $HCl$ to yield chlorobenzene $(C_6H_5Cl)$ and nitrogen gas $(N_2)$. Therefore,the correct set of reagents is $NaNO_2 / HCl, 273-278 \ K ; Cu_2Cl_2 / HCl$.

Which of the following sets of reagents convert aniline to chlorobenzene?

Similar Questions

Urea is

What is formed when benzylamine reacts with nitrous acid?

Which of the following compounds acts as the strongest base in its aqueous solution?

Arrange the following compounds according to increasing order of boiling points: $n-C_4H_9OH$ $(A)$, $n-C_4H_9NH_2$ $(B)$, $n-C_4H_{10}$ $(C)$, and $C_2H_5NHC_2H_5$ $(D)$.

What is the product formed when a primary amine reacts with a ketone?

Vedclass Test Series

Exam Paper Generator

Online Exam Module