Which of the following species is planar?

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(A) To determine the geometry,we calculate the hybridization of the central atom:$1$. For $CO_3^{2-}$: The central carbon atom is $sp^2$ hybridized wi

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$CO_3^{2-}$

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(A) To determine the geometry,we calculate the hybridization of the central atom:$1$. For $CO_3^{2-}$: The central carbon atom is $sp^2$ hybridized with no lone pairs,resulting in a trigonal planar geometry.$2$. For $NH_2^-$: The nitrogen atom has $2$ bond pairs and $2$ lone pairs,resulting in $sp^3$ hybridization and a bent ($V$-shaped) geometry.$3$. For $PCl_3$: The phosphorus atom has $3$ bond pairs and $1$ lone pair,resulting in $sp^3$ hybridization and a trigonal pyramidal geometry.Therefore,only $CO_3^{2-}$ is planar.

Molecule	Geometry
$(a) SnCl_2$	$(i)$ Angular (or) Bent
$(b) XeF_4$	$(ii)$ See-saw
$(c) ClF_3$	$(iii)$ Square pyramidal
$(d) IF_5$	$(iv)$ $T$-shape
-	$(v)$ Square planar

Similar Questions

The number of species having a non-pyramidal shape among the following is:
$A$. $SO_{3}$
$B$. $NO_{3}^{-}$
$C$. $PCl_{3}$
$D$. $CO_{3}^{2-}$

Match the following?
Molecule Geometry
$(a) SnCl_2$ $(i)$ Angular (or) Bent
$(b) XeF_4$ $(ii)$ See-saw
$(c) ClF_3$ $(iii)$ Square pyramidal
$(d) IF_5$ $(iv)$ $T$-shape
- $(v)$ Square planar

In which of the following conversions does a planar compound change into a non-planar compound?
$(a)$ $ClF_3 \rightarrow ClF_4^{-}$
$(b)$ $NH_2^{-} \rightarrow NH_4^{+}$
$(c)$ $I_3^{+} \rightarrow I_3^{-}$
$(d)$ $SO_2 \rightarrow SO_3$

The correct structure of $PCl_3F_2$ is

The geometry of $H_2S$ and its dipole moment are

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