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(C) Let us analyze the geometry of each species:$(a)$ $ClF_3$ is $T$-shaped (planar) and $ClF_4^{-}$ is square planar (planar). No change in planarity

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only $b$

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(C) Let us analyze the geometry of each species:$(a)$ $ClF_3$ is $T$-shaped (planar) and $ClF_4^{-}$ is square planar (planar). No change in planarity.$(b)$ $NH_2^{-}$ is $V$-shaped (planar) and $NH_4^{+}$ is tetrahedral (non-planar). Thus,it changes from planar to non-planar.$(c)$ $I_3^{+}$ is angular (planar) and $I_3^{-}$ is linear (planar). No change in planarity.$(d)$ $SO_2$ is angular (planar) and $SO_3$ is trigonal planar (planar). No change in planarity.Therefore,only $(b)$ involves a change from a planar to a non-planar compound.

Molecule	Geometry
$(a) SnCl_2$	$(i)$ Angular (or) Bent
$(b) XeF_4$	$(ii)$ See-saw
$(c) ClF_3$	$(iii)$ Square pyramidal
$(d) IF_5$	$(iv)$ $T$-shape
-	$(v)$ Square planar

In which of the following conversions does a planar compound change into a non-planar compound?
$(a)$ $ClF_3 \rightarrow ClF_4^{-}$
$(b)$ $NH_2^{-} \rightarrow NH_4^{+}$
$(c)$ $I_3^{+} \rightarrow I_3^{-}$
$(d)$ $SO_2 \rightarrow SO_3$

Similar Questions

Match the following?
Molecule Geometry
$(a) SnCl_2$ $(i)$ Angular (or) Bent
$(b) XeF_4$ $(ii)$ See-saw
$(c) ClF_3$ $(iii)$ Square pyramidal
$(d) IF_5$ $(iv)$ $T$-shape
- $(v)$ Square planar

The correct order of bond angles of the molecules $SiCl_4$,$SO_3$,$NH_3$,and $HgCl_2$ is:

The structure of ammonia $(NH_3)$ is.......

The $O-N-O$ bond angle is maximum in

The shapes of $BrF_5$ and $XeF_4$,respectively are

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In which of the following conversions does a planar compound change into a non-planar compound?$(a)$ $ClF_3 \rightarrow ClF_4^{-}$$(b)$ $NH_2^{-} \rightarrow NH_4^{+}$$(c)$ $I_3^{+} \rightarrow I_3^{-}$$(d)$ $SO_2 \rightarrow SO_3$