Which of the following statements are not cor | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) is incorrect: For water, $K_f = 1.86 	ext{ K kg mol}^{-1}$ and $K_b = 0.512 	ext{ K kg mol}^{-1}$, so $K_f > K_b$.$B$ is incorrect: Since $K_f >

Vedclass · Accepted Answer

$A, B$ and $D$ only

Vedclass · Answer

(C) is incorrect: For water, $K_f = 1.86 	ext{ K kg mol}^{-1}$ and $K_b = 0.512 	ext{ K kg mol}^{-1}$, so $K_f > K_b$.$B$ is incorrect: Since $K_f > K_b$, the depression in freezing point $(\Delta T_f = K_f m)$ is larger than the elevation in boiling point $(\Delta T_b = K_b m)$ for the same molality $m$.$C$ is correct: Osmotic pressure is preferred because its magnitude is large even for dilute solutions, making it easier to measure for macromolecules like proteins and polymers.$D$ is incorrect: The dimerised form of benzoic acid involves hydrogen bonding between the carboxyl groups, represented as $(C_6H_5COOH)_2$ with the structure $C_6H_5 - C(OH)=O \cdots HO - C(O) - C_6H_5$.Therefore, statements $A, B$, and $D$ are incorrect.

Similar Questions

The difference between the boiling point and freezing point of an aqueous solution of urea containing $10.0 \ kg$ of water is $100.2372 \ ^oC$. How many grams of urea are dissolved in the solution? (Given: $K_b = 0.513 \ K \ kg \ mol^{-1}$,$K_f = 1.86 \ K \ kg \ mol^{-1}$)

In a mixture of camphor in nitrogen gas,the physical states of the solute and the solvent are,respectively:

The freezing point of an aqueous solution is $-0.186^oC$. If the molal elevation constant and molal depression constant of the solvent are $0.512$ and $1.86$ respectively,then the elevation in boiling point is .......... $^oC$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module