Which of the following statements is correct | vedclass

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(A) In the Daniell cell,$Zn$ acts as the anode and $Cu$ acts as the cathode.At the anode,oxidation occurs: $Zn_{(s)} \longrightarrow Zn^{2+}_{(aq)} +

Vedclass · Accepted Answer

$Zn$ is the reducing agent.

Vedclass · Answer

(A) In the Daniell cell,$Zn$ acts as the anode and $Cu$ acts as the cathode.At the anode,oxidation occurs: $Zn_{(s)} \longrightarrow Zn^{2+}_{(aq)} + 2e^-$.At the cathode,reduction occurs: $Cu^{2+}_{(aq)} + 2e^- \longrightarrow Cu_{(s)}$.Since $Zn$ undergoes oxidation,it acts as a reducing agent.Since $Cu^{2+}$ undergoes reduction,it acts as an oxidising agent.The overall cell reaction is $Zn_{(s)} + Cu^{2+}_{(aq)} \longrightarrow Zn^{2+}_{(aq)} + Cu_{(s)}$.Comparing this with the given options,option $(A)$ states that $Zn$ is a reducing agent,which is correct. Note: Option $(D)$ in the original text had a typo in the reaction notation ($Zn^{+}Cu^{2+}$ instead of $Zn+Cu^{2+}$),but $(A)$ is fundamentally correct.

Which of the following statements is correct for the cell $Zn|Zn^{2+} \parallel Cu^{2+}|Cu$?

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