Which of the following will not produce CH_4 | vedclass

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(D) $CH_3MgBr$ is a Grignard reagent which acts as a strong base. It reacts with compounds containing acidic hydrogen atoms (like $-OH$,$-NH_2$,$-SH$,

Vedclass · Accepted Answer

$1,4-$Pentadiene $(CH_2=CH-CH_2-CH=CH_2)$

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(D) $CH_3MgBr$ is a Grignard reagent which acts as a strong base. It reacts with compounds containing acidic hydrogen atoms (like $-OH$,$-NH_2$,$-SH$,$-COOH$,$-SO_3H$) to produce methane $(CH_4)$ gas.$1.$ $C_6H_5SO_3H + CH_3MgBr \rightarrow C_6H_5SO_3MgBr + CH_4 \uparrow$$2.$ $CH_3NH_2 + CH_3MgBr \rightarrow CH_3NHMgBr + CH_4 \uparrow$$3.$ $CH_3CH_2OH + CH_3MgBr \rightarrow CH_3CH_2OMgBr + CH_4 \uparrow$In $CH_2=CH-CH_2-CH=CH_2$ ($1$,$4$-pentadiene),the hydrogen atoms attached to $sp^2$ hybridized carbons are not acidic enough to react with $CH_3MgBr$ to produce $CH_4$. Therefore,it will not produce $CH_4$ gas.

Which of the following will not produce $CH_4$ gas when reacted with $CH_3MgBr$?

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