Which one is the correct outer electronic con | vedclass

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(C) The atomic number of chromium $(Cr)$ is $24$. The expected electronic configuration is $[Ar] \, 3d^4 \, 4s^2$. However,due to the extra stability

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(C) The atomic number of chromium $(Cr)$ is $24$. The expected electronic configuration is $[Ar] \, 3d^4 \, 4s^2$. However,due to the extra stability associated with half-filled $d$-orbitals,one electron from the $4s$ orbital shifts to the $3d$ orbital. Thus,the actual ground state configuration is $[Ar] \, 3d^5 \, 4s^1$. This corresponds to $5$ unpaired electrons in the $3d$ subshell and $1$ unpaired electron in the $4s$ subshell,which is represented by option $(C)$.

Which one is the correct outer electronic configuration of chromium $(Cr)$?

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