Which one of the following complexes will hav | vedclass

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(D) For a complex to have $\Delta_0 = 0$ (Crystal Field Stabilization Energy,$CFSE = 0$),the electronic configuration must be such that the stabilizat

Vedclass · Accepted Answer

$\left[Mn(SCN)_6\right]^{4-}$

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(D) For a complex to have $\Delta_0 = 0$ (Crystal Field Stabilization Energy,$CFSE = 0$),the electronic configuration must be such that the stabilization from $t_{2g}$ electrons is exactly cancelled by the destabilization from $e_g$ electrons. This occurs for $d^5$ high-spin complexes where $t_{2g}^3 e_g^2$. $CFSE = (3 	imes -0.4 \Delta_0) + (2 	imes 0.6 \Delta_0) = -1.2 \Delta_0 + 1.2 \Delta_0 = 0$. For $\mu = 5.96 \ B.M.$,the number of unpaired electrons $(n)$ must be $5$,as $\mu = \sqrt{n(n+2)} \ B.M. = \sqrt{5(7)} = \sqrt{35} \approx 5.92-5.96 \ B.M.$. In $\left[Mn(SCN)_6ight]^{4-}$,$Mn$ is in $+2$ oxidation state $(3d^5)$. $SCN^-$ is a weak field ligand,leading to a high-spin configuration $t_{2g}^3 e_g^2$. Thus,it satisfies both conditions.

$I$. $NCS^{-}$	$II$. $S^{2-}$
$III$. $en$	$IV$. $SCN^{-}$

Which one of the following complexes will have $\Delta_0 = 0$ and $\mu = 5.96 \ B.M.?$

Similar Questions

The correct order of decreasing field strength of the below given ligands is
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