Which one of the following reactions will not | vedclass

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(D) $CH_3-CH_2-OH$ on oxidation with $CrO_3 - H_2SO_4$ (Jones reagent) gives acetic acid $(CH_3-COOH)$ because it is a strong oxidizing agent. The oth

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$CH_3-CH_2-OH \xrightarrow{CrO_3 - H_2SO_4}$

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(D) $CH_3-CH_2-OH$ on oxidation with $CrO_3 - H_2SO_4$ (Jones reagent) gives acetic acid $(CH_3-COOH)$ because it is a strong oxidizing agent. The other reactions produce acetaldehyde $(CH_3-CHO)$: $(A)$ Dehydrogenation of ethanol: $CH_3-CH_2-OH \xrightarrow[573 \ K]{Cu} CH_3-CHO + H_2$ $(B)$ Reduction of nitrile: $CH_3-CN \xrightarrow[(ii) H_2O]{(i) DIBAL-H} CH_3-CHO$ $(C)$ Wacker process: $CH_2=CH_2 + O_2 \xrightarrow[H_2O]{Pd(II)/Cu(II)} CH_3-CHO$

Item-$I$	Item-$II$
$I$. Benzene	$P$. $HCl$ and $SnCl_2, H_3O^{+}$
$II$. Benzonitrile	$Q$. $H_2, Pd-BaSO_4, S$ and quinoline
$III$. Benzoyl Chloride	$R$. $CO, HCl$ and $AlCl_3$

Which one of the following reactions will not form acetaldehyde?

Similar Questions

Identify compound $X$ in the following sequence of reactions:

Identify the product of the following reaction:
$C_6H_6 + CO + HCl \xrightarrow{AlCl_3} \text{Product}$

Identify $X$ and $Y$ in the reactions given below:

The correct match between Item-$I$ (starting material) and Item-$II$ (reagent) for the preparation of benzaldehyde is :
Item-$I$ Item-$II$
$I$. Benzene $P$. $HCl$ and $SnCl_2, H_3O^{+}$
$II$. Benzonitrile $Q$. $H_2, Pd-BaSO_4, S$ and quinoline
$III$. Benzoyl Chloride $R$. $CO, HCl$ and $AlCl_3$

For the reaction below, the structure of the product $Q$ is:

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