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(A) Dehydration in acidic conditions typically proceeds via an $E1$ mechanism involving the formation of a carbocation intermediate. However,for $\bet

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$4-$hydroxy$-2-$pentanone

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(A) Dehydration in acidic conditions typically proceeds via an $E1$ mechanism involving the formation of a carbocation intermediate. However,for $\beta$-hydroxy carbonyl compounds,dehydration is significantly facilitated because the resulting product is a conjugated $\alpha,\beta$-unsaturated carbonyl system,which is thermodynamically very stable.In option $A$,the compound is $4$-hydroxy-$2$-pentanone. This is a $\beta$-hydroxy ketone. Upon dehydration,it forms a conjugated system (pent$-3-$en$-2-$one). The presence of the carbonyl group at the $\beta$-position relative to the hydroxyl group makes the $\alpha$-hydrogen acidic,facilitating the elimination of water to form a stable conjugated enone.Other options do not form a conjugated system as readily or at all under these conditions. Therefore,$4$-hydroxy-$2$-pentanone is the most readily dehydrated.

Which one of the following will be most readily dehydrated in acidic condition?

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