Which option is correct for curve a and b?| C | vedclass

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(B) In the given graph,curve $a$ represents exponential growth,which is characterized by unlimited resources and is $J$-shaped. The equation for expon

Vedclass · Accepted Answer

$\frac{dN}{dt} = rN$ for $a$,$\frac{dN}{dt} = rN(\frac{K-N}{K})$ for $b$; Exponential curve for $a$,Logistic curve for $b$

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(B) In the given graph,curve $a$ represents exponential growth,which is characterized by unlimited resources and is $J$-shaped. The equation for exponential growth is $\frac{dN}{dt} = rN$.Curve $b$ represents logistic growth,which occurs when resources are limited,leading to a carrying capacity $(K)$. This curve is $S$-shaped (sigmoid). The equation for logistic growth is $\frac{dN}{dt} = rN(\frac{K-N}{K})$.Therefore,for curve $a$,the equation is $\frac{dN}{dt} = rN$ and it is an exponential curve. For curve $b$,the equation is $\frac{dN}{dt} = rN(\frac{K-N}{K})$ and it is a logistic curve. Thus,option $(b)$ is correct.

Which option is correct for curve $a$ and $b$?
| Curve | Equation | Type of Curve |
| :--- | :--- | :--- |
| $a$ | ? | ? |
| $b$ | ? | ? |

Similar Questions

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Which option is correct for curve $a$ and $b$?| Curve | Equation | Type of Curve || :--- | :--- | :--- || $a$ | ? | ? || $b$ | ? | ? |