Which two of the following five physical para | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The dimensions of the given physical parameters are as follows:$(a)$ Energy density: $	ext{Energy} / 	ext{Volume} = [ML^2T^{-2}] / [L^3] = [ML^{

Vedclass · Accepted Answer

$(a), (d)$

Vedclass · Answer

(A) The dimensions of the given physical parameters are as follows:$(a)$ Energy density: $	ext{Energy} / 	ext{Volume} = [ML^2T^{-2}] / [L^3] = [ML^{-1}T^{-2}]$$(b)$ Refractive index: $	ext{Ratio of speeds} = 	ext{Dimensionless} = [M^0L^0T^0]$$(c)$ Dielectric constant: $	ext{Ratio of permittivities} = 	ext{Dimensionless} = [M^0L^0T^0]$$(d)$ Young's modulus: $	ext{Stress} / 	ext{Strain} = [ML^{-1}T^{-2}] / [M^0L^0T^0] = [ML^{-1}T^{-2}]$$(e)$ Magnetic field: $	ext{Force} / (	ext{Charge} 	imes 	ext{Velocity}) = [MLT^{-2}] / ([IT] 	imes [LT^{-1}]) = [MT^{-2}I^{-1}]$Comparing the dimensions,we see that $(a)$ Energy density and $(d)$ Young's modulus have the same dimensions,$[ML^{-1}T^{-2}]$.Therefore,the correct option is $(a), (d)$.

Which two of the following five physical parameters have the same dimensions?
$(a)$ Energy density
$(b)$ Refractive index
$(c)$ Dielectric constant
$(d)$ Young's modulus
$(e)$ Magnetic field

Similar Questions

Dimensional formula for torque is

Write the magnitude and dimensional formula of $\frac{1}{\sqrt{\mu_0 \epsilon_0}}$.

The velocity of a particle depends upon time as $v = a + bt + ct^2$. If the velocity is in $m/s$,the unit of $a$ will be:

Which of the following physical quantities has a unit but no dimensions?

Write the dimensional formula for the intensity of radiation.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Which two of the following five physical parameters have the same dimensions?$(a)$ Energy density$(b)$ Refractive index$(c)$ Dielectric constant$(d)$ Young's modulus$(e)$ Magnetic field