White light is used to illuminate two slits i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) In a $YDSE$ setup,the path difference $\Delta x$ at a point on the screen at a distance $y$ from the central axis is given by $\Delta x = \frac{yd

Vedclass · Accepted Answer

Both $(A)$ and $(C)$

Vedclass · Answer

(D) In a $YDSE$ setup,the path difference $\Delta x$ at a point on the screen at a distance $y$ from the central axis is given by $\Delta x = \frac{yd}{D}$.For a point directly in front of one of the slits,the distance from the central axis is $y = \frac{d}{2}$.Substituting this into the path difference formula: $\Delta x = \frac{(d/2)d}{D} = \frac{d^2}{2D}$.For destructive interference (missing wavelengths),the path difference must be an odd multiple of half the wavelength: $\Delta x = (2m + 1) \frac{\lambda}{2}$,where $m = 0, 1, 2, ...$.Equating the two expressions: $\frac{d^2}{2D} = (2m + 1) \frac{\lambda}{2}$.Solving for $\lambda$: $\lambda = \frac{d^2}{(2m + 1)D}$.For $m = 0$,$\lambda = \frac{d^2}{D}$.For $m = 1$,$\lambda = \frac{d^2}{3D}$.Thus,both wavelengths $\frac{d^2}{D}$ and $\frac{d^2}{3D}$ are missing.

White light is used to illuminate two slits in a $YDSE$. The separation between the slits is $d$ and the screen is at a distance $D (D >> d)$ from the slits. At a point on the screen directly in front of one of the slits,which of the following wavelengths are missing?

Similar Questions

In Young's double-slit experiment,the amplitudes of two sources are $3a$ and $a$ respectively. The ratio of intensities of bright and dark fringes will be: (in $: 1$)

Which of the following is a true statement if,in Young's double-slit experiment,the separation between the slits is gradually increased?

In a Young's double slit experiment,the slit separation is $0.2 \ cm$,the distance between the screen and slit is $1 \ m$. The wavelength of the light used is $5000 \ \mathring{A}$. The distance between two consecutive dark fringes (in $mm$) is

For sustained interference fringes in a double-slit experiment,the essential condition$(s)$ is/are:
$1$. Sources must be coherent.
$2$. The intensities of the two sources must be equal.
Here,the correct option$(s)$ is/are:

Young's double-slit experiment is performed with a wavelength of $550 \,nm$. If the distance between the two slits is $1.10 \,mm$ and the distance between the screen and the slits is $1 \,m$,then the distance between two consecutive bright or dark fringes is .....$mm$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module