Why can we not determine the order of a reaction by taking into consideration the balanced chemical equation?
(N/A) The balanced chemical equation represents the overall stoichiometry of a reaction but does not necessarily reflect the mechanism or the rate-determining step.
$1.$ The order of a reaction is an experimental quantity,whereas the stoichiometry is derived from the balanced equation.
$2.$ Many reactions are complex and occur in multiple steps. The rate of the overall reaction is determined by the slowest step in the mechanism.
$3.$ For example,consider the reaction: $CHCl_3 + Cl_2 \rightarrow CCl_4 + HCl$. Based on the stoichiometry,one might incorrectly predict a second-order reaction,but the experimental rate law is $Rate = k[CHCl_3][Cl_2]^{1/2}$,which is of order $1.5$.
$4.$ Thus,the order of a reaction cannot be determined simply by looking at the balanced chemical equation.
$1.$ The order of a reaction is an experimental quantity,whereas the stoichiometry is derived from the balanced equation.
$2.$ Many reactions are complex and occur in multiple steps. The rate of the overall reaction is determined by the slowest step in the mechanism.
$3.$ For example,consider the reaction: $CHCl_3 + Cl_2 \rightarrow CCl_4 + HCl$. Based on the stoichiometry,one might incorrectly predict a second-order reaction,but the experimental rate law is $Rate = k[CHCl_3][Cl_2]^{1/2}$,which is of order $1.5$.
$4.$ Thus,the order of a reaction cannot be determined simply by looking at the balanced chemical equation.
Explore More
Similar Questions
The rate of reaction is determined by the slow step of the reaction. This step is called:
Easy
View SolutionFill in the blanks:
$1.$ The rate of reaction depends on the ........... step.
$2.$ In a bimolecular reaction,the reaction takes place with ........... species and ........... .
$3.$ The order of reaction is determined by ...........
$1.$ The rate of reaction depends on the ........... step.
$2.$ In a bimolecular reaction,the reaction takes place with ........... species and ........... .
$3.$ The order of reaction is determined by ...........
Difficult
View SolutionConsider the reaction $2 \ A + 2 \ B \rightarrow C + 2 \ D$. If the concentration of $A$ is doubled at constant $B$,the rate increases by a factor of $4$. If the concentration of $B$ is doubled at constant $A$,the rate is doubled. What is the rate law?
The rate constant for a reaction is $10.8 \times 10^{-5} \ mol \ L^{-1} \ s^{-1}$. The order of the reaction is .......
Easy
View SolutionThe reaction of hydrogen and iodine monochloride is given as :
$H_{2(g)} + 2ICl_{(g)} \rightarrow 2HCl_{(g)} + I_{2(g)}$
This reaction is of first order with respect to $H_{2(g)}$ and $ICl_{(g)}$. The following mechanisms were proposed:
Mechanism $A$ :
$H_{2(g)} + 2ICl_{(g)} \rightarrow 2HCl_{(g)} + I_{2(g)}$
Mechanism $B$ :
$H_{2(g)} + ICl_{(g)} \rightarrow HCl_{(g)} + HI_{(g)}$ ; (slow)
$HI_{(g)} + ICl_{(g)} \rightarrow HCl_{(g)} + I_{2(g)}$ ; (fast)
Which of the above mechanism$(s)$ can be consistent with the given information about the reaction?
$H_{2(g)} + 2ICl_{(g)} \rightarrow 2HCl_{(g)} + I_{2(g)}$
This reaction is of first order with respect to $H_{2(g)}$ and $ICl_{(g)}$. The following mechanisms were proposed:
Mechanism $A$ :
$H_{2(g)} + 2ICl_{(g)} \rightarrow 2HCl_{(g)} + I_{2(g)}$
Mechanism $B$ :
$H_{2(g)} + ICl_{(g)} \rightarrow HCl_{(g)} + HI_{(g)}$ ; (slow)
$HI_{(g)} + ICl_{(g)} \rightarrow HCl_{(g)} + I_{2(g)}$ ; (fast)
Which of the above mechanism$(s)$ can be consistent with the given information about the reaction?
DifficultAIPMT 2007
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo