Why is KO_{2} paramagnetic? | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The compound $KO_{2}$ consists of $K^{+}$ and $O_{2}^{-}$ ions. The superoxide ion $O_{2}^{-}$ has $13$ valence electrons. According to molecular

Vedclass · Accepted Answer

Due to the presence of one unpaired electron in the $\pi^{*} 2p$ molecular orbital.

Vedclass · Answer

(B) The compound $KO_{2}$ consists of $K^{+}$ and $O_{2}^{-}$ ions. The superoxide ion $O_{2}^{-}$ has $13$ valence electrons. According to molecular orbital theory,the electronic configuration of $O_{2}^{-}$ is $\sigma 1s^{2}, \sigma^{*} 1s^{2}, \sigma 2s^{2}, \sigma^{*} 2s^{2}, \sigma 2p_{z}^{2}, \pi 2p_{x}^{2} = \pi 2p_{y}^{2}, \pi^{*} 2p_{x}^{2} = \pi^{*} 2p_{y}^{1}$. The presence of one unpaired electron in the $\pi^{*} 2p$ molecular orbital makes $O_{2}^{-}$ paramagnetic.

Why is $KO_{2}$ paramagnetic?

Similar Questions

$N_2$ and $O_2$ are converted into monocations,$N_2^+$ and $O_2^+$ respectively. Which of the following statements is wrong?

Calculate the bond order of $N_2, O_2, O_2^+$ and $O_2^-$.

$N_2$ and $O_2$ are converted to monocations $N_2^+$ and $O_2^+$ respectively. Which statement is wrong?

Which of the following statements is correct?

Vedclass Test Series

Exam Paper Generator

Online Exam Module