Why is FeO_{(s)} not formed in stoichiometric | vedclass

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(D) In a crystal of $FeO$,some of the $Fe^{2+}$ ions are replaced by $Fe^{3+}$ ions. Three $Fe^{2+}$ ions are replaced by two $Fe^{3+}$ ions to mainta

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(D) In a crystal of $FeO$,some of the $Fe^{2+}$ ions are replaced by $Fe^{3+}$ ions. Three $Fe^{2+}$ ions are replaced by two $Fe^{3+}$ ions to maintain electrical neutrality. This results in a metal deficiency defect,where the ratio of $Fe$ to $O$ is less than $1:1$ (typically $Fe_{0.95}O$). Therefore,it is not formed in stoichiometric composition.

Why is $FeO_{(s)}$ not formed in stoichiometric composition?

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