Why is aniline soluble in aqueous $HCl$?
(N/A) Aniline is a base that reacts with the acid $HCl$ to form a salt called anilinium chloride $(C_6H_5NH_3^+Cl^-)$.
This salt is an ionic compound,which makes it highly soluble in water.
The reaction is:
$C_6H_5NH_2 + HCl_{(aq)} \rightarrow C_6H_5NH_3^+Cl^-_{(aq)}$
This salt is an ionic compound,which makes it highly soluble in water.
The reaction is:
$C_6H_5NH_2 + HCl_{(aq)} \rightarrow C_6H_5NH_3^+Cl^-_{(aq)}$
Explore More
Similar Questions
In the following reactions,$P$,$Q$,$R$,and $S$ are the major products.
(image)
The correct statement about $P$,$Q$,$R$,and $S$ is
(image)
The correct statement about $P$,$Q$,$R$,and $S$ is
MediumIIT 2023
View SolutionThe major products $A$ and $B$ formed in the following reaction sequence are :
DifficultJEE MAIN 2021
View SolutionThe compound $X (C_{7}H_{9}N)$ reacts with benzene sulphonyl chloride to give $Y (C_{13}H_{13}NO_{2}S)$ which is insoluble in alkali. The compound $X$ is
MediumKVPY 2013
View Solution$CH_{3}CH_{2}Br$ $\xrightarrow[\Delta]{aq. KOH} A$ $\xrightarrow[\Delta]{KMnO_{4} / H^{+}} B$ $\xrightarrow[\Delta]{NH_{3}} C$ $\xrightarrow[alkali]{Br_{2}} D$. '$D$' is
Which of the following is the strongest base?
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo